This.mWmParams = new WindowManager. Log.e("FloatView-","宽"+mScreenWidth+"-"+"高"+mScreenHeight) 08-23 15:38:21.021: E/AndroidRuntime(4200): Caused by: : Unable to add window 418c0b68 - permission denied for this window type Problem: maifest.
MWindowManager.getDefaultDisplay().getMetrics(dm) MWindowManager = (WindowManager) mContext.getSystemService(Context.WINDOW_SERVICE) ĭisplayMetrics dm = new DisplayMetrics() WmParams.alpha = (1.0f - ((BRIGHTNESS + 55) / (float) 255)) WindowManager.LayoutParams p new WindowManager.LayoutParams( // Shrink the window to wrap the content rather than filling the screen, , // Display it on top of other application windows, but only for the current user, // Don't let it grab the input focus WindowManager. GetColor(this, sharedPreferences.getInt(SharedPrefs.KEY_COLOR_ID, R.color.black))) WmParams.flags = _NOT_TOUCHABLE | _NOT_FOCUSABLE | _LAYOUT_IN_SCREEN | _WATCH_OUTSIDE_TOUCH | _FULLSCREEN
* These windows are normally placed above all applications, but behind Your Part: count imagecursor.getCount() thumbnails new Bitmapcount May cause this. * user interaction with the phone (in particular incoming calls). These are non-application windows providing The key to the relationship between window and view is windows manager Addview () this method. WmParams = new WindowManager.LayoutParams(_PARENT, Wm = (WindowManager) getApplicationContext().getSystemService(Context.WINDOW_SERVICE) line: windowManager.addView(surfaceView, layoutParams) : Unable to create service:. MyView = new LinearLayout(getApplicationContext()) myView = new LinearLayout(new ContextThemeWrapper(getApplicationContext(), R.style.Theme_Transparent), null, 0)
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